Double merge two data frames in r -


मेरे पास दो डेटाफ्रेम हैं 

  df1 = data.frame (साइट्स = सी ("ए "बी", "सी"), कुल = सी (12,635)) df2 = data.frame (साइट 1 = सी ("ए", "ए", "बी"), साइट 2.2 = C ("बी", "सी", "सी"), स्कोर = सी (60,70,80))   
 मुझे डेटाफ्रेम तैयार करने के लिए उन्हें मर्ज करने की आवश्यकता है  
  df3 = data.frame (साइट 1 = सी ("ए", "ए", "बी"), साइट 2.2 = सी ("बी", "सी", "सी") , स्कोर = सी (60,70,80), साइट .1। कुल = सी (12,12,6), साइट 2.क्षेत्र = सी (6,35,35))   
 ऐसे डबल मर्ज करने के लिए सबसे सरल तरीके से कोई सलाह? धन्यवाद   
 
 
 बस  मर्ज  दो बार:  
  एक्स एंड एलटी; - मर्ज (df2, df1, all.x = TRUE, द्वारा.x = "Site.2", by.y = "Sites", सॉर्ट = FALSE) मर्ज (x, df1, all.x = TRUE , By.x = "Site.1", by.y = "Sites", सॉर्ट = FALSE) साइट 1 साइट .2 कुल कुल कुल 1.x 1 एबी 60 6 12 2 एसी 70 35 12 3 बीसी 80 35 6

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more