javascript - Element (background-image) opacity, but no border opacity -


I know how to do it, how to do it, but I have to do without the element Ambiguity, backend-image ambiguity I do not want to modify the image in the Image Editor, so I am looking for the ambiguity set by the CSS. possible?

In my CSS below, I want to modify the "disabled" status with a sharp no-opacity limit. Please advice ...

Examples of use:

Button style: 

  div.button, div.button: hover {background: none; Border: 2px solid # 6C7B8B; Range radius: 8px; Explicit: none; Color: Transparent; Cursor: indicator; Display: Inline-block; Filter: Alpha (Opacity = 100); -M-filter: "Progress: DXimage Transforms. Microsoft. Elfa (Opacity = 100)"; Float: None; Height: 24px; Margin-down: 0 pixels; Margin-left: 3px; Margin-right: 0 pixels; Margin-top: 7px; Opacity: 1; -Moostness: 1; Profile: None; Hidden flurry; Padding: None; Vertical-alignment: top; Width: 24px; }   
   Click the effect:    
  div.button: active {left: 1px ; Status: Relative; Top: 1px; }   
   Additional styles are disabled for the status:    
  div.disabled, div. Disabled: hover {cursor: default; Filter: Alpha (Opacity = 50); -M-filter: "Progress: DXimage Transforms. Microsoft. Alpha (Opacity = 50)"; Opacity: 0.50; -Moziness: 0.50; } Div.disabled: active {left: 0px; Status: Relative; Top: 0 pixels; }   
   Extra style for position:    
  div.on, div.on: Hover {boundary: 2px solid # 007FFF; }    
 
 
 You are just in that situation - you want to be transparent background, but non Transparent content (whose count of bounds)  
 So there is no such  background-image-opacity  in CSS3, you can only create a transparent image or position on one another with two elements, lower picture image ( As suggested by the answer here).  
 But in your case the image will be sufficient to shadow it can be done using a transparent image from the beginning, for example, but change the underlying  background color . Or you can  
  & lt; Div class = "button" title = "zoom!" & Gt; & Lt; Img src = "icon.gif" alt = "specs" /> & Lt; / Div & gt;   
 with  
  div.button.disabled img {opacity: .5; }   
 which can be more emotionally understood, too. You should be away from those inline styles.  
 ()

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more