vb.net - Click Button Event in VB that displays a message about user input -


I have a very quick and simple question, I am learning programming in C # and VB and I want to make it Required GUI application in Windows Form with Visual Studio will prompt this GUI to enter the user in the integer. I believe this part of mine is fine but then I have to click on a button which will convert the user's entry into an integer and indicate whether the user was successful or not. I think that I have a conversion correctly, but I am having trouble displaying that message, if the user succeeds, I will have to know how to work out the click method in VB Will allow you to appear. Any help with this would be greatly appreciated. The following is the code that I have already written for this project: 

  public class form 1 private sub-evaluation input () String input = ValueTextBox.Text if the input is incomplete (ifnumeric InputValue) then MessageBox.Show (InputValue & "is a number.") Either MessageBox.Show (InputValue & "is not a number.") End if end sub personal sub button 2_Click (Sender as System .Object, and System. EventArgs) Handle Button2.Click 'Continue Button End Sub Private All Button 1_Click ( As deputy from. Object system as Istm. Ivars Agriks) button 1 handles. Exit Button as the Button Button Dialog Result Button = Message Box Show _ ("Are you sure you want to get out of the application?", "Message", message box, Yes No, Message Box icon. Warning, Message Box, Default Button, Button 1) If Button = Windows.Forms.DialogResult.Yes Then Me.Close () Other 'Do not End End End End Class    
 
 
 I understand my question correctly, so y will need to change just where:  
  Private sub button 2_Click (The sender in the form of the system object, And system.AventArange__ handles the buttons. Click the Continue button Input () End sub   
 When you press the button 2, it will call the EvolutionAut input sub and will display a message accordingly.

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more