static typing - Definition of statically typed and dynamically types -
Which of the two definitions is correct?
- Static typed - Type matching is checked at compile time (and can therefore only be applied to compiled languages) < Li> Dynamically typed - Type Match is checked at run time, or not at all. (This term can be applied for compiled or interpreted language)
- Staticly typed - assigned to type variable So that I will say 'x type int' .
- Dynamically typed - types are assigned to values (if at all), then I would say
Which is correct, or is not quite right?
Which is correct, or is not quite right?
The first pair of definitions is close, but not quite right.
Static typed - compile time of type matching (and therefore can only be applied to compiled languages)
It is difficult, I think that if any language was used, but the type of investigation was done before the execution began, then it will still be typed steadily. OCaml REPL, an example of this, leaves almost technically compiled (and type-check) source code in its own byte code and then interprets the byte code.
Dynamically typed - Type matches are checked in run-time, or not at all.
rather:
Dynamic typed - Type is done on check
Static type Done - The type variable is assigned, so that I would say that 'x type type' is.
Dynamically typed - Assign types to values (if at all), then I would say that 'x holds an integer
The variables are irrelevant though you see clearly only the type in the source code of the languages that are typed in several static and functional definitions, but all sub-communications also have static types, for example,
"Foo" + 3 usually a fixed type of The error is because you can not add a string to an variable but it does not include any variables.
- Dynamically typed - types are assigned to values (if at all), then I would say
- Staticly typed - assigned to type variable So that I will say 'x type int' .
Comments
Post a Comment