html - Jquery find a span tag with specific style -


मेरे पास span टैग td के अंदर तालिका विशिष्ट शैली के साथ रंग: लाल । मुझे उस स्पैन टैग को ढूंढना है और इसे नीचे छिपाया जाना है I

HTML: 

  & lt; table class = "table_1 "& gt; & LT; tbody & gt; & LT; टीआर & gt; & LT; टीडी & gt; & Lt; span id = "गतिशील रूप से उत्पन्न" शैली = "रंग: लाल;" & gt; त्रुटि! इसे सही करें। & Lt; / span & gt; & Lt; / टीडी & gt; & LT; टीडी & gt; & LT; अवधि & gt; // तीन अलग-अलग साइटों के लिए तीन लिंक्स & lt; a & gt; & Lt; / a & gt; & Lt; a & gt; & Lt; / a & gt; & Lt; a & gt; & Lt; / a & gt; & Lt; / span & gt; & Lt; / टीडी & gt; & Lt; / टीआर & gt; & LT; टीआर & gt; & Lt; / टीआर & gt; & Lt; / tbody & gt; & Lt; / तालिका & gt;    
  Jquery:    प्रत्येक (फ़ंक्शन (n) {$ (this)। Find ('td: eq (0)')। (मिलते समय) 'Span')। Html ("");});   
 उपरोक्त jquery कोड दोनों  span  टैगों को छिपाते हुए भले ही वे अलग-अलग  td  में हों क्या मुझसे कुछ गलत हो रही है? मैं सिर्फ पहले स्पैन टैग को छुपाना चाहता हूं जिसमें इसमें त्रुटि संदेश है I क्या कोई तरीका है?   
 
 
 आम तौर पर आप एक  वर्ग  को डाल देंगे या टीडी (जैसे 'त्रुटि'), फिर  छिपाने () :  
  & lt; span id = "dynamically-generated" class = "error" & gt; त्रुटि! इसे सही करें। & Lt; / span & gt; ... $ ('table.table_1 .error')। Hide ();   
 छिपाना एचटीएमएल ('') के मुकाबले ज्यादा खूबसूरत है, क्योंकि छिपाने () सामग्री को नष्ट नहीं करेगा। इसलिए यदि आप बाद में त्रुटि प्रदर्शित करना चाहते हैं, तो बस  दिखाएं ()  को कॉल करें :)  
 अंत में, आपको अपने सीएसएस में लाल रंग देना चाहिए:  
  .error {color: red; }

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more