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I am starting to learn regex and I do not know if I understand it correctly.

I have a problem with changing the function because it does not replace the character in a string that I want to change.

Here is my code: 

  public class TestingRegex {public static void key (string algos []) {string string = "hello% l and +++ o_wow _ + L% D & # "; Four special family [] = {'%', '%', 'and', '_'}; (Four SC: special caterers) {if (string contains (sc + "")) string = string.replaceAll (sc + "", "\\" + sc); } System.out.println ("new string:" + string); }}   
 Output is similar to original nothing changed.  
 I should have the output:  Hell \% l & amp; +++ o \ _Wor \ _ ++ l \% d \ & amp; ## .  
 Please help in advance thanks.   
 
 
 The reason is not working: To create you need a four backslash in a Java string There is a single "real" backslash    string = string.replaceAll (Sc, "\\\" + +);   
 This is not the right way to do this. You do not want to loop at all:  
  string string = "hello% l & amp; +++ o_Wor _ ++ l% d & amp; # "; String = string.replaceAll (" [% & amp; _] "," \\\\ $ 0 ");   
 And you have done  < P>  Explanation:   
     
  •   [% & amp; _]  matches the three characters you want to change  
  •   $ 0  is the result of the match, so  
  •   "\\\\ $ 0"  means "a backslash plus whatever It corresponds with Rijks. "  
     
     WARNING: This solution is not obvious whether any of those characters  already  have already escaped or not.  
      hollow \%   
     will be  
      hollow \\%   
     you do that Do not want to have this problem?

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