java - How to check entered String in a loop with condition? -


I want to write a program that gives the user a string of four boundaries (for example 10 characters Checks)). If the entry in the string is more than 10 characters, then the user should re-sign again until the user enters a valid string (one word of 10 characters) until the user enters a valid string.

I already have some piece of code for it but it does not work yet, because I do not know how to prompt the user again or other easy way to start How to start the process? 

  System.out.print ("Input:"); String inputts = input Screenplay (); While (inputChars.length ()> 10) {System.out.print ("Input:"); String inputts = input Screenplay (); // Here is a mistake now} System.out.print ("Output:"); System.out.print ("10 characters in login");   
 I'm more than just 10 words, then check the entered word, then leave it and prompt the user to enter a word again which is more than 10 Not a character. I am not good in Java yet, so if this question is stupid, then explain to me how to solve it. Thanks in advance   
 
 
 Look at your loop:  
  while inputChars .length ()> 10) {System.out.print ("Input:"); String inputts = input Screenplay (); }   
 The second line of the loop body  resale  to the  inputcharts  variable. You can not do this because it is already in the area. You just want to  replace the previous value :  
  inputChars = input.readString ();   
 To avoid duplication, you should also consider restructuring of your code:  
  string input chords; Do {System.out.print ("Input:"); InputChars = input.readString (); } While (inputChars.length ()> 10);   
 Note that in order to follow the normal Java naming conventions, I named the  input  variable as  input . I would actually change both  input  and  inputts  more descriptively - in particular, what is the meaning of input data  mean  at this time

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more