- Where Developers Learn, Share, & Build Careers


I thought I'm Ruby huge when I wrote this: 

  # this hash Hash = {'Portugal' = & gt; 1, 'France' = & gt; 2, 'USA' = & gt; 3} # country_id input comes from country_name =. (Hash .select {| k, v | v == country_id.to_i} .first || []). First   
 This is to be removed in the right way, the country's name and if the country is not found then it does not fail.  
 I am completely happy with it.  
 Although my tutor says that according to readability it can be customized, length and performance!  
 What can be more clear / sharp than this?  
 Please give advice   
 
 
 OK, it seems that your tutor is right :)  
 You can do this:  
  hash.invert [country_id.to_i] # will work on all editions   
 Or, as suggested by @littlecegian  
  hash (country_id.to_i) will work on # 1.9   
 or, as is done by @steenslag Recommended  
  hash.index (country_id.to_i) will work on # 1.8 and 1.9, with a warning on 1.9  with / past> 
 full example:  
  hash = {'Portugal' = & gt; 1, 'France' = & gt; 2, 'USA' = & gt; 3}% w [2 3 1 Bla]. Country_id | # All versions country_name = hash.invert [country_id.to_i] # 1.9 only country_name = hash.key (country_id.to_i) # 1.8 and 1.9, 1.9 country_name with a warning = hash.index (country_id.to_i) printf "country_id =% S, country_name =% s \ n ", country_id, country_name end   
 will print:  
  country_id = 2, country_name = France country_id = 3 , Country_name = USA country_ id = 1, country_name = Portugal country_ id = blah, country_name =   
 see it running

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more