How to parse a String in Java? -


यह मेरा कोड है: 

  import java.io. *; Import java.util। *; सार्वजनिक वर्ग परीक्षण {सार्वजनिक स्थिर शून्य मुख्य (स्ट्रिंग [] आर्ग्स) {स्कैनर = नए स्कैनर (System.in); PrintStream आउट = System.out; स्ट्रिंग इनपुट = .next (); स्ट्रिंग आउटपुट = ""; चार सी = 0; Int count = 0; Int countInput = input.length (); के लिए (इंट i = 0; i & lt; countInput; i ++) {यदि (मैं == 0) {c = input.charAt (i); गिनती ++; } Else {if (c == input.charAt (i)) {count ++; } और {आउटपुट = आउटपुट + गणना + "" + c; गणना = 1; C = input.charAt (i); out.println (उत्पादन); }}} आउटपुट = आउटपुट + गणना + "" + c; out.println (उत्पादन);  
  
 Blockquote> 
 आउटपुट:  
 
 5A3n3f2k   
 मुझे इसे किसी तरह ठीक करना होगा:  
  स्ट्रिंग इनपुट = इन ।आगामी();   
 मुझे लगता है कि  args  को कहीं भी इस्तेमाल किया जाना है, मुझे यकीन नहीं है कि कहां कहां हैं।   
 
 
 आपका प्रोग्राम तर्क ठीक है। लेकिन आप जो करना चाहते हैं उसके आधार पर, आपको  स्कैनर  वर्ग की आवश्यकता नहीं होगी।  
 यदि आप अपना इनपुट आर्गेंसेस एरे से आना चाहते हैं:  main ( स्ट्रिंग [] args) , तो आपको अपने इनपुट को असाइन करना होगा:  
  स्ट्रिंग इनपुट = आर्ग्स [0];   
 लेकिन हे, क्या हुआ अगर आपने तर्क दिए बिना प्रोग्राम चलाया? यह एक अपवाद फेंक देगा, इसलिए आपको कुछ प्रकार की त्रुटि से निपटने की आवश्यकता है:  
  स्ट्रिंग इनपुट = ""; यदि (args.length & gt; 0) {input = args [0]; }

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more