arrays - What does the declaration void** mean in the C language? -


I am starting to learn C and read the following code: 

  public zero * * List_to_array (list * thiase) {int size = list_size (thiz); Zero ** Array = Molok 2 (size (zero *) * size); Int i = 0; List_rewind (thiz); For (i = 0; i   
 I do not understand the meaning of  zero ** . Can anyone explain this with some examples?  
 
 
 Zero is an indicator indicator for zero (unspecified type). This means that there is no address for the memory space in the variable (memory location), where there is an address for another memory location, and that is not specified where it is stored. In the case of this question it is an indicator for an array of zero * pointsers.  
 SidNote: A zero pointer can not be distinguished, but one can be zero.  
  zero * one [100]; Zero ** AA = A;   
 By doing this, AR must be able to do this [17] to achieve the 18th element of the array.  
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