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Is this an easy way to find out? What is the lowest (most negative) number that can be presented by two complementes of 7-bit? Show how to convert the number into two complementary presentations.

The least number is -2 ^ 6 . To find out the negative number of a negative number in the supplement of 2 (aka its full value) flip the bits and add one then (- 1) * 1000001 = 0111110 + 1 = 0111111 = 1000000 - 1 = 2 ^ 6-1 . As you can see that there is less than 1000001 and it is less than that: 1000000 . We are getting this full value:

(- 1) * (100000) = (-1) * (100001-1) = (-1) * (100001) + 1 = (2 ^ 6-1) +1 = 2 ^ 6 .

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