datetime - Python: Effective way to convert ambiguous hours into time object? -


I have a list of strings, which is as follows: 

  4: 00- 5: 00PM 11: 00-2: 00 PM 12: 00-1: 00 PM 11: 00-1: 00AM   
 And I try to find an effective way of creating the object twice (I think this is the only way to keep track of a limit of time, which I will later add to a date object). It is clear to humans what we mean 11: 00-1: 00 AM, but considering what is an effective way to change it:  
  datetime.time (23, 0 ) Datetime.time (1, 0)   
 Take my current view for the first time, and prepare a PM and AM version, take timeliness with the end time (which is specified) , And less than two differences are correct.   
 
 
 This is a simple implementation.  
  & gt; & Gt; & Gt; Def Timelines: ... T1, T2 = Timestar Split ("-") ... Timeformat = "% I:% M% p" ... t1AM = datetime.datetime.strptime (t1 + " AM ", time format) ... t1PM = datetime.datetime.strptime (t1 +" PM ", time format) ... t2 = datetime.datetime.strptime (T2, time format) ... ... if ( T2 - T1AM) .seconds & lt; (T2-t1PM) .seconds: ... return t1AM.time (), t2.time () ... else: ... return t1PM.time (), t2.time ()> & gt; & Gt; & Gt; Timrange ("11: 00-2: 00 pm") (datetime.time (11, 0), datetime.time (14, 0)) gt; & Gt; & Gt; Timrange ("4: 00-5: 00 pm") (datetime.time (16, 0), datetime.time (17, 0)) gt; & Gt; & Gt; Time range ("11: 00-1: 00AM") (datetime.time (23, 0), datetime.time (1, 0)) gt; & Gt; & Gt; Timrange ("11: 00-2: 00 pm") (datetime.time (11, 0), datetime.time (14, 0)) gt; & Gt; & Gt; Timeline ("12: 00-1: 00 pm") (datetime.time (12, 0), datetime.time (13, 0))   
 this  time  Object, but if you need it, then you can roll it into the Detach object.

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