php - Display dropdown based on checked box -


I have a group of checkboxes 'box' Now I want my dropdown list to show name based on the checkbox database .

Code: 

  $ sql = "Choose empname from mstEmp where teamtype = '$ d' by command 'empname"; $ ObjDB- & gt; SetQuery ($ SQL); $ Res = $ objDB-> GetQueryReference (); If (! $ Res) exit ("Error in SQL: $ sql"); If $ ($ objDB-> GetNumRows ($ res)>) {while ($ line = mysql_fetch_row ($ res)) {print ("& lt; option value = '{$ row [0]}' & Gt; {line row [0]} & lt; / option & gt; "); }} Mysql_free_result ($ res);

1.select.jsp 

  & lt ; % @ Page Import = "java.sql. *"% "% & Gt; & Lt; Html & gt; & Lt; Top & gt; & Lt; Script type = "text / javascript" & gt; Function Shodeta () {if (document.form.check.checked == true) {xmlHttp = GetXmlHttpObject () var url = "select2.jsp"; XmlHttp.onreadystatechange = stateChanged xmlHttp.open ("GET", url, true) xmlHttp.send (null)}} function stateChanged () {if (xmlHttp.readyState == 4 || xmlHttp.readyState == "full") { Document.getElementById ("name") innerHTML = xmlHttp.responseText. }} GetXmlHttpObject () {var xmlHttp = null; Try {xmlHttp = new XMLHttpRequest (); } Hold (e) {try {xmlHttp = new ActiveXObject ("Msxml2.XMLHTTP"); } Hold (e) {xmlHttp = new ActiveXObject ("Microsoft.XMLHTTP"); }} Return xmlHttp; } & Lt; / Script & gt; & Lt; / Head & gt; & Lt; Body & gt; & Lt; Form name = "form" & gt; & Lt; Br> & Lt; Br> & Lt; Input type = "checkbox" id = "check" onclick = "showData ();" & Gt; & Lt; Div id = 'name' & gt; & Lt; B & gt; Select data & lt; / B & gt; & Lt; Select name = 'name' & gt; & Lt; Option value = '- 1' & gt; & Lt; / Options & gt; & Lt; / Select & gt; & Lt; / Div & gt; & Lt; / Form & gt; & Lt; / Body & gt; & Lt; / Html & gt;

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more