Ruby unpack to Python -


I'm trying to convert some Ruby code into Python. I'm having trouble with this line: 

  digest :: MD5 digist (message) .mpack ('L *')   
 I think Is that I should use the  struct  module and  hashlib , but if I do:  
  struct.unpack ('L', Hashlib.md5 (message) .digest ())   
 I get this error:  
  struct.error: unpack length of 4 bytes of a object Required   
 What should I do? Thanks,  
 Rubik  
 P.S. Output should be a list of 4 x 32 bits:  
  irb (main): 039: 0> Digest :: MD5 digest ('hash'). Unpack ('L *') = & gt; [631892218, 19671 99 614, 3683860, 94, 4130231798]  "post-text" itemprop = "text"> 
 There is no support for arbitrary length ( *  Operator). You must specify a criminal manually.  
 Fortunately, the Composition module assigns you a certain length,  and  the Hashlib module tells you how many bytes are expected before   By entering  L  you can specify the number of times to apply the pattern. And there is a special hash in the  hashlib  library that tells you how many bytes is a specific hash.  
 To combine these:  
  Structspec = '% iL'% (hashlib.hash ('md5'). Digest_size / 4) struct.unpack (structspec , Hashlib.md5 (message) .digest ())   
 If you do not want to cut code here  4 , then you  struct.calcsize < / Code> to  L  size: unsigned long:  
  structspec = '% iL'% (hashlib.hash ('md5' ). Digest_size / struct.calcsize ('L')) struct.unpack (structspec, hashlib.md5 (message) .digest ()) In fact, on 64-bit platforms such as my Mac,  L  is 8 bytes, so calculate the latter Ehd is important if you have different architectures.

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