asp.net - How to make 2 asp:Menu control render in the same line? -


I am trying to add a second menu control to a second row with an existing row but I do Can not manage for & lt; Div class = "hidden skeptical" & gt; & Lt; ASP: menu id = "navigation menu" runat = "server" cssClass = "menu" enabled widget = "false" styleball = "wrong" orientation = "horizontal"> gt; & Lt; Items & gt; & Lt; Asp: MenuItem NavigateUrl = "~ / Default.aspx" text = "home" /> & Lt; Asp: MenuItem NavigateUrl = "~ / about.aspx" text = "About" /> & Lt; / Item & gt; & Lt; / ASP: Menu & gt; & Lt; ASP: Menu id = "small menu" run = "server" CssClass = "smallMenu" enabled ViewState = "false" includes styleballcock = "wrong" orientation = "horizontal" & gt; & Lt; Items & gt; & Lt; Asp: MenuItem NavigateUrl = "~ / Settings.aspx" text = "Settings" /> & Lt; Asp: MenuItem NavigateUrl = "~ / Admin.aspx" text = "admin" /> & Lt; / Item & gt; & Lt; / ASP: Menu & gt; & Lt; / Div & gt;

Tried to format it using CSS but it is not working. The second menu appears in a new line what I am doing wrong here? 

  div.menu {padding: 4px 0px 4px 8px; Swim left; Width: 500px; } Div.smallMenu {padding: 4px 8px 4px 0px; Width: 300px; float right; }  Edit:  I can reveal them in the same line if I put them into the divis and float the other one on the right but now half right (right) Appears on   
 
 
 It seems like you have to debug something like using your browser's client-side debugging tool This is what you describe (the division of the menu on the right), as if the CSS Warrenis hierarchy is somewhat above the influence of that div's position.  
 One more thing you can try is to get more nest of the menu:  
  & lt; Div & gt; & Lt; DIV style = "float: left;" & Gt; & Lt; DIV style = "float: true;" & Gt; & Lt; ASP: Menu / & gt; & Lt; / Div & gt; & Lt; ASP: Menu / & gt; & Lt; / Div & gt; & Lt; / Div & gt;   
 ETA: A post with a similar issue is the top 2 answers (7 and 5 digits respectively, in the form of this writing) There are some things you can try and do some other link

Comments

Post a Comment

Popular posts from this blog

Python SQLAlchemy：AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema' -

I tried to create a new database in my project, but when I run the script, I get this error, I have another project, this type of definition worked before, but now it gets a single error. I am using Python 2.7.8 and the version of SQLAlchemy module is 0.9.8. By the way, using a project flask- SQLAlchemy, it works well, I'm confused. Traceback information is as follows: Traceback (most recent call final): File "D: / Projects / IOM / db_create.py", line 4, & lt; Module & gt; From the models the base file "D: \ Projects \ OO-IM \ models.py", in line 15, in the & lt; Module & gt; Column ( 'followed_id', int (), ForeignKey ( 'user.id')) file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ schema.py", line 369, __new__ schema = metadata. Schema file "C: \ Python27 \ lib \ site-packages \ SQLAlchemy \ SQL \ elements.py", line 662, AttributeError in __getattr__ key): Neither 'column' object nor ...
Read more

java - How not to audit a join table and related entities using Hibernate Envers? -

I use Eners to be hibernate to audit my institutions. I have an audit entity, Foo , which includes a list & lt; Bars & gt; However, I do not want to audit the bar institutions, in the form of properties, I have written that: @inti @edicated public class Foo {@JoinTable (name = "T_FOO_BAR", joinColumns = @JoinColumn (name = "FOO_ID"), inverseJoinColumns = @JoinColumn (Name = "BAR_ID")) @ManyToMany (Cascade = Persist) @ Indited (targetAuditMode = RelationTargetAuditMode.NOT_AUDITED ) Public listing & lt; Bars & gt; GetBars () {Return bars; }} Now, I want to retrieve an amendment of foo : AuditReader reader = AuditReaderFactory.get (GetEntityManager ()); FU modification = (FU) reader.CreativeTeA () .entensEtrevision (Foo Class, 42) .getSingleResult (); Unfortunately, when I want to retrieve all the data (i.e. when it loads lazy times ), error me ORA-00942: table or view is not present , because Tried to query this: Sel...
Read more

mongodb - CakePHP paginator ignoring order, but only for certain values -

While pagging my user model in kppp, I can sort with some values, but not others. For example, I can order results from created or email , for example, but username or reputation seems to come back order by arbitrary command for example with a list of users: $ this-> paginate = array ('condition' => array ( 'User.is_active' = & gt; true), 'border' => 24, 'order' => array ('User.created' => DESC)); Works as expected, but $ this - & gt; Paged = array ('conditions' = & gt; array (' user.isIactive '= & gt; true),' border '= & gt; 24,' command '= & gt; array (' user repeats' = ' & Gt; DESC ')); No, no. I first thought that this could be a database issue, but when I search the database directly, sorted as expected. Note: I am using Mangodebi with the Mongo DB plugin of Ichikawa for the KPPHP; Pagnetizing users are used to work properl...
Read more