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Will a webpage be affected with CSS / Javascript / jquery etc? Let's show the letters of the text and each individual letter at a time, it would be good to create a 'zoom-up' effect, ideally it would be nice to display a little differentiation on each letter, but it would not be important. What I am trying to achieve is changing the style of each individual letter, as you are the mouse on them, this text is not a link, it is also not dynamic which means There is a static paragraph of the text and I want to apply this effect to each letter. Any help is appreciated. Thank you. / P> You can try the plugin. Alternatively, you span each letter and then enliven it: $ ("selector"). ({FontSize: "22"}, 300);}, function () {$ (this) .mate ({fontSize: "16"}, 300);})

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I am working on oyoth authentication for my app and I'm planning to use Oauth2. Someone can tell if Gmail supports the attracting inbox by Oauth2 access-token. I have noticed that it is possible by Oauth1 token but I found that OAuth1 support is now excluded by Google. No, just now OAuth 1.0.

python - Combining multiple regex substitutions -

I am trying to remove some things from a block of text using regex. I have all my patterns ready, but I think the overlapping can not be able to remove two (or more). For example: import r1 = r'i am 'r2 = r'am foo' text = 'I am foo' re.sub (r1, '', Text) # Returns' foo 're.sub (r2,' ', text) # Returns' How do I change both records together and end with an empty string? I have finished using a slightly modified version: def clean (self, text): pattern Mask for Pattern = Baitier (LAN): To match in the Rifidator (pattern, text): r = Category (match, start), match.and () Mask [R] = 'X' * Lane (R) returns ''. (Character for character, bit in bit (text, mask) in zip) You can always call it re.sub Shown can not form. You can use re.finditer to find them all. Each match will give you a match object, in which .start and .end indicate their posts. You can collect them all together, and then finally...

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The IOS noob question is here, though I hope that it is not a repetition of iOS 4+ targeting to develop on XCode 4.3 I I am struggling to get guidance on how to get a list of Bluetooth devices. It seems that there are many Bluetooth interfaces but please correct me if I got the following error for the dedicated purposes: Core Bluetooth: Bluetooth LE (Bluetooth 4.0) gamekit: Peer-peer based on session ID EAAccessory: MFI Bluetooth device in XCode 3.0 There is also the useless "Bluetooth Manager" API. Can someone share with me how to get a list of Bluetooth devices with the current device running on my app? I am only interested in make, model, identifier (or serial number), I really do not need to communicate with the devices, just to be sure. thank you in advanced. Try downloading these examples and try to resolve your needs: Hope will be a helper

spring - "HTTP Status 405 - Request method 'POST' not supported" on form submit -

Trying to make a very simple form in Spring / Hibernate, it should add the entry to the database. This is an example that has worked for me, so it is weird that I am getting this error. But this is what it is that is it. The page is with this form: prefix @ taglib uri = "http://java.sun.com/jsp/Jstl/ core" = "C"%> & Lt;% @ taglib uri = "http://www.springframework.org/tags/form" prefix = "form"% & gt; & Lt; Html & gt; & Lt; Head & gt; & Lt; Title & gt; Add Ownership Game & lt; / Title & gt; & Lt; / Head & gt; & Lt; Body & gt; & Lt; H1 & gt; Add ownership game & lt; / H1> & Lt; Br / & gt; & Lt; Br / & gt; & Lt; C: url var = "saveGameeUrl" value = "/ games / save.html" / & gt; & Lt; Form: Form Model Attribute = "Game" method = "Post" action = "$ {saveGameUrl}" & gt; & Lt; Form: label...

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I am setting up celery to run using variables from your virtual environment, Demunik. But when I run $ sudo /etc/init.d/celeryd , I start unknown order. Use 'celeryd_multi' type 'manage.py help' I have set up the following: CELERYD_CHDIR = "/ home / MyUser / projects / MyProject "ENV_PYTHON =" / home / MyUser / .virtualenvs / MyProject / bin / python "cELERYD_MULTI =" $ ENV_PYTHON $ CELERYD_CHDIR / manage.py celeryd_multi " when I run from $ /home/myuser/.virtualenvs/myproject/bin/python / home / MyUser / projects /myproject/manage.py celeryd_multi command line, it works fine. Any thoughts? I'll gladly post any other code to you :) Thank you! > the operating proper environment and it pulls packages from /home/myuser/.virtualenvs/myproject /... when you start sudo /etc/init.d/celeryd as you root Cereal which is probably not active in virtualenv /root/.virtualenvs/, then such a thing is also present and thus it...

sql - How can I return unique rows when using an INNER JOIN in MySQL? -

I have 3 tables: links, keywords, and keyword_link can have many keywords in one link, and one in many links Can be the only keyword. Used to join keyword_link to link and keyword . When I run the following query, several lines of the same link are returned because multiple keywords match. How do I modify this query to return unique rows? SELECT links * Include link 'links' from keywords_links.link_id = Add keywords_completions on ID Add keywords to keywords. Keywords = _links.keyword_id where the keyword. Keyword IN ('php', 'sql', 'html', 'css') Select the easiest way DISTINCT after select : select different links. * ... ... But perhaps a more efficient solution would be to write to you that it does not need to make a difference in each column: SELECT a. * Join INNER from the link (SELECT a.link_id Inner Join keyword with keyword b on one) Keyword_id = b.id and b.keyword IN ('php', 'sql', 'html...